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Help with one more trig problem! Screenshot is attached
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cos(a+b) = cosa.cosb - sina.sinb sin(a+b) = sina.cosb + cosa.sinb tan (a+b) = (tana+tanb) / (1-tana.tanb)
now let's check the signs of alpha and beta: alpha is in the third region where sin is and cos are both (-) and beta is in region 4 where sin is - and cos is +
Okay
sin a = -3/5, cos a = -4/5, sin b= -3/sqrt(13) and cos b = 2/sqt(13)
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tan a = 3/4 and tan b = 3/2
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