Question

The area of a rectangle is 21ft , and the length of the rectangle is 1ft less than twice the width. Find the dimensions of the rectangle.

Answer 1

Area of rectangle = lb

Answer 2

Try to put this into algebraic expression

Answer 3

You are given that:

\[\large{\rm{length} = 2 \times width - 1}\]

Answer 4

Now, we have :

\[\large{\rm{length = l; width = b}}\]

Answer 5

Length: 2x-1
Width: x
Area: Length times width, so 2x^2-x=21

Answer 6

@vishweshshrimali5 double variable is complicated to explain

Answer 7

I was going to write l in terms of b :)

Good work @leejaeho2002 :D

Answer 8

good job both of you @vishweshshrimali5 @leejaeho2002

Answer 9

\[\large{\rm{l = 2b-1}}\]

Thus:

\[\large{\rm{Area = l\times b = (2b-1)(b)}}\]

Answer 10

thx

Answer 11

Thanks @study100 :)

Answer 12

Do u get it homework