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Mathematics 14 Online
OpenStudy (anonymous):

Simplify

OpenStudy (vishweshshrimali5):

@Huyani your question ? :)

OpenStudy (anonymous):

Gimme one long minute bc it's gonna take a while

OpenStudy (vishweshshrimali5):

Take your time :)

OpenStudy (anonymous):

@vishweshshrimali5 are they allowed to ask us to give them the exact answers.

OpenStudy (uri):

one long minute = one minute=60 sec.

OpenStudy (anonymous):

\[\frac{ \frac{ a }{ 2x+h }-\frac{ a }{ 2x } }{ h }\]

OpenStudy (vishweshshrimali5):

Suppose if the question is such that you can't give a hint without complete solution, then you are allowed to provide solution with detailed explanation for each step

OpenStudy (anonymous):

@uri good point xD

OpenStudy (vishweshshrimali5):

For example, if some one asks what is \sqrt{4} then we can't help without giving the answer. SO, we can use examples, explanations etc. :)

OpenStudy (anonymous):

Uri plz

OpenStudy (vishweshshrimali5):

\[\large{\cfrac{ \cfrac{ a }{ 2x+h }-\cfrac{ a }{ 2x } }{ h }}\]

OpenStudy (vishweshshrimali5):

First of all you can take a common from numerators of both fractions in numerator of main fraction.

OpenStudy (vishweshshrimali5):

\[\large{\cfrac{ \cfrac{ \color{red}{a} }{ 2x+h }-\cfrac{\color{red}{ a} }{ 2x } }{ h }}\]

OpenStudy (anonymous):

uh.......?

OpenStudy (vishweshshrimali5):

The `red a` :)

OpenStudy (anonymous):

Yes, what can I take from them? *You're dealing with a clueless person sorry*

OpenStudy (anonymous):

You need a common denominator. So |dw:1406527367072:dw|

OpenStudy (anonymous):

x?

OpenStudy (anonymous):

Wait, shouldn't it be (2xa+ah)-2xa?

OpenStudy (anonymous):

what is 2xa -2xa and no I didn't add the parenthese, but it's 2xa -2xa -ah

OpenStudy (anonymous):

so, (-ah/4x^2+2xh)/h

OpenStudy (anonymous):

and simplify, you get |dw:1406528283932:dw|

OpenStudy (anonymous):

or |dw:1406528356050:dw|

OpenStudy (anonymous):

And that's the final answer?

OpenStudy (anonymous):

Yes :)

OpenStudy (anonymous):

Alrighty, thanks! I'll try the next one on my own, and I'll tag you in a post if I'm stuck

OpenStudy (anonymous):

np, vish was helping alot too haha

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