Question

Having trouble with this question 27x^2-9x=0 the book is sayin g the answer is x=0 x=1/3. Do not get how they get the answer

Answer 1

9x(3x-1)=0

Answer 2

\[27 x^2-9 x=0,9 x(3 x-1)=0\]
find the two answers by equating each=0

Answer 3

3x-1=0 add 1 to both side 3x=1 x=1/3

Answer 4

correct.

Answer 5

other 9 x=0,x=0

Answer 6

why is is it 9X0

Answer 7

?

Answer 8

when x*y=0, then either x=0 or y=0

Answer 9

I got y=0

Answer 10

here either 9x=0,x=0
or3 x-1=0
x=1/3

Answer 11

x=1/3?

Answer 12

got it thanks a lot Surjithayer

Answer 13

so basically factor 9x(3x-1)=0
1st equation 3x-1=0 add 1 to both sides 3x=1
divide by 3X you get 3x=1 then 9x=0
dived by 9 on both sides 0/9= 0

Answer 14

4x^2-x=-9x
x(4x-1)=-9x
4x-1=-9x
-4x on each side
-1=-13x
divide by -13
x=1/13

Answer 15

thanks

Answer 16

but the answer is saying 2 what am I doing wrong is this equation

Answer 17

sorry -2

Answer 18

yeah its correct

Answer 19

why i am getting 1/13 i do not get -2 like in the back of the book

Answer 20

\[4 x^2-x=-9 x,4 x^2-x+9 x=0,4x^2+8 x=0,4 x(x+2)=0\]
either 4 x=0,x=0/4=0
x+2=0
x=-2