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Mathematics 16 Online
OpenStudy (anonymous):

Based on the graph below, what are the solutions to the equation f(x) = g(x)?

OpenStudy (anonymous):

OpenStudy (anonymous):

x = -3.7, 0.5, 3.4 x = -1, 1, 2 x = -2, 2, 3 x = -2, 0.6, 3.4

OpenStudy (anonymous):

@ninjasandtigers

OpenStudy (anonymous):

do you know what the functions are?

OpenStudy (anonymous):

nope

OpenStudy (anonymous):

it just said f(x)=g(x)

OpenStudy (anonymous):

you see the point where f(x) crosses g(x)?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

those are your solutions

OpenStudy (anonymous):

ya but it doesnt match the choices

OpenStudy (anonymous):

it matches d

OpenStudy (anonymous):

ok thanks

OpenStudy (anonymous):

welcome

OpenStudy (anonymous):

i have one more

OpenStudy (anonymous):

The table below shows the values of f(x) and g(x) for different values of x. One of the functions is a quadratic function, and the other is an exponential function. Which function is most likely increasing quadratically?

OpenStudy (anonymous):

x f(x) g(x) 1 3 3 2 6 9 3 11 27 4 18 81 5 27 243

OpenStudy (anonymous):

f(x), because it grows faster than g(x) g(x), because it will not intersect f(x) g(x), because it grows slower than f(x) f(x), because it grows slower than g(x)

OpenStudy (anonymous):

i want to say f(x) is the quadratic because g(x) is growing exponentially

OpenStudy (anonymous):

so i think d

OpenStudy (anonymous):

ok thank you and i have one more and this is the last one

OpenStudy (anonymous):

Emily wants to hang a painting in a gallery. The painting and frame must have an area of 31 square feet. The painting is 5 feet wide by 6 feet long. Which quadratic equation can be used to determine the thickness of the frame, x?

OpenStudy (anonymous):

OpenStudy (anonymous):

4x2 + 22x - 1 = 0 4x2 + 22x + 31 = 0 x2 + 11x - 1 = 0 x2 + 11x + 31 = 0

OpenStudy (anonymous):

the outer dimensions would be 2x+5 and 2x+6

OpenStudy (anonymous):

so what would the answer be

OpenStudy (anonymous):

4x^2+22x+30=31

OpenStudy (anonymous):

did you get it?

OpenStudy (anonymous):

@liorafanny

OpenStudy (anonymous):

yeah thanks

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