Question

In △JKL, solve for x.

Answer 1

17.32

38.16 <- my answer correct me if I'm wrong plz thanks

66.73

74.89

Answer 2

Well we know the angle, the side opposite the angle, and we want the side adjacent to the angle

Seems like a tangent problem

\[\large \tan(27) = \frac{34}{x}\]
\[\large x = \frac{34}{\tan(27)}=?\]