Question

Jimmy needs to pass a college class. On his first exam he got a 44% and on his 2nd exam he didn't do any better and got a 66%. What percent does jimmy need to get on his last exam so that he can pass with a C.

Answer 1

44/100x-->first exam
66/100x-->second exam

Answer 2

what am I doing with this?

Answer 3

solving for x?

Answer 4

Well i cant really solve for x now can i

Answer 5

Yea I don't think that is it

Answer 6

yes u are right

Answer 7

and how are you getting 110?

Answer 8

oh alright so then

Answer 9

i think 88/100

Answer 10

nope

Answer 11

I feel as if there is something im not seeing

Answer 12

was 88/100 not the answer?

Answer 13

i was not confident with my answer.i think other way also 44%-x=56% and 66%-x=34% so total x=90%.i was not sure .whether my answer is correct

Answer 14

first 44/100x so 11/25

Answer 15

well i do know that 44%-x=56% equals -3/25
while 66%-x=34% equal 8/25

Answer 16

second 33/50

Answer 17

@robtobey

Answer 18

i think this will be the right answer 90%

Answer 19

see in first exam 11/25 so left is 14/25 and in second 33/50 and left is 17/50 and addin both we get 45/50*100=90

Answer 20

14/25+17/50=45/50
so 45/50x*100=90

Answer 21

is it correct

Answer 22

probably a 77%

Answer 23

@dumbcow

Answer 24

@ganeshie8 answer for oldschooldexter

Answer 25

assuming equal weights for the exams and 70 as passing with a C

--> (44+66+X)/3 = 70

44+66+X = 210
X = 100

Answer 26

so c=100%

Answer 27

yeah

Answer 28

if we take 100 then x=210

Answer 29

(44+66+x)/3=100
means x=210

Answer 30

hmm no x=190 in that case

66+44 = 110
110 + 190 = 300

Answer 31

yes

Answer 32

x=190 also correct?

Answer 33

bit confusing from yesterday.i want to put him correct solution

Answer 34

well like i said assuming the class grade consists of only the 3 equally weighted exams
then its simply the average of the 3 exam scores

--> (44+66+X)/3 = class grade
if he wants at least a 70% or C
then X = 100%, he needs a perfect score on final exam

Answer 35

i dont know the correct solution.but it makes a sense

Answer 36

@ganeshie8

Answer 37

help him