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Mathematics 8 Online
OpenStudy (anonymous):

PLEASE HELP AND WILL GIVE MEDAL! Simplify and select the answer with the appropriate restrictions for the variables. 6x^2-3x/3x^2

OpenStudy (taylorterminate):

Factor the numerator and the denominator: (3x² + 6x)/(x² - 2x - 8) = [3x(x + 2)] / [(x - 4)(x + 2)] Assuming that x ≠ -2, cancel the common factor of (x + 2) in the numerator and denominator to give 3x/(x - 4)

OpenStudy (anonymous):

okay thanks but I didn't have that as one of the options for an answer. :/

OpenStudy (taylorterminate):

oops sorry 3x/x-4

OpenStudy (anonymous):

hahah thanks

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