Question

4^2x-3=32 solve exponential equation

Answer 1

is it like this \(\normalsize\color{blue}{ 4^{2x-3} = 32 }\)

Answer 2

So do you know how to use exponential and logarithm, like \(\normalsize\color{blue}{ log{2^x=x} }\)

Answer 3

Yes @xapproachesinfinity

Answer 4

32 you can write as a power \(\normalsize\color{blue}{ 32= 2^5 }\)

Answer 5

I suggest that you rewrite \(\normalsize\color{blue}{ 4^{2x=3}=2^{2(2x-3)} }\)

Answer 6

what do you see know

Answer 7

forget about log thing that I said earlier just use exponent properties

Answer 8

\(\normalsize\color{blue}{ 4^{2x-3} =2^{2(2x-3)}=2^{4x-6} }\)

Answer 9

can you do the rest?

Answer 10

@jeshana

Answer 11

Yes thank u

Answer 12

You're welcome. can you post your answer later

Answer 13

I got 11/4 = 2.75 @xapproachesinfinity

Answer 14

Correct! Good job!