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OpenStudy (anonymous):
What is the value of p in the equation x^2+16y=0? (Parabola question)
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OpenStudy (xapproachesinfinity):
x^2=4py use this to find what p is
OpenStudy (anonymous):
So p=-4?
OpenStudy (xapproachesinfinity):
Yes!
OpenStudy (anonymous):
Thank you!
OpenStudy (xapproachesinfinity):
You're welcome
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