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need some help with this problem 4y^2=10y-3 what i have done so far = -4y^2=10y-3 imputing in the equation -b square root b^2-4ac/2a stuck where to go from here? please help
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changed the eqation to -4x^2+10y-3=0
What is your question?
after i put it in stranded form i am difficulty putting it in -b sqaure root b^2-4ac/2ac formula and getting the answer.
So you want to solve this? -4x^2+10y-3=0
yes
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Solve for x? or Y? or what?
solve for y
y=(2x^2)/5 + 3/10
At least that's what I got for Y
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this is the exact answer an qustion and i am not getting the answer that the book is getting. Suppose to solve using quadratic formula.
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