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Chemistry 18 Online
OpenStudy (superhelp101):

Determine the rate law, including the values of the orders and rate law constant, for the following reaction using the experimental data provided. A + B yields products

OpenStudy (superhelp101):

hold up let me post the rest :)

OpenStudy (superhelp101):

Trial [A] [B] Rate 1 0.15 M 0.12 M 1.3 × 10-2 M/min 2 0.30 M 0.12 M 2.6 × 10-2 M/min 3 0.15 M 0.24 M 5.2 × 10-2 M/min

OpenStudy (abhisar):

come here @superhelp101

OpenStudy (superhelp101):

I'm here !

OpenStudy (abhisar):

Ok let's see In Trial 1 to 2 X doubled and rate also doubled...ok ?

OpenStudy (superhelp101):

yas

OpenStudy (abhisar):

In trail 1 to 3 y doubled and rate is 4 times

OpenStudy (superhelp101):

yup

OpenStudy (abhisar):

So doubling X doubles rate and doubling Y quadruples the rate.

OpenStudy (abhisar):

Rate = [x][y]^2

OpenStudy (abhisar):

isn't it ?

OpenStudy (superhelp101):

oh then one the post one year ago there waz like a formula ??

OpenStudy (abhisar):

No there is no formula for this question. The one year ago post was xplaining the same thing.

OpenStudy (abhisar):

It's a conceptual question

OpenStudy (abhisar):

are you getting it ?

OpenStudy (superhelp101):

i think so, yeah

OpenStudy (abhisar):

sure ?

OpenStudy (superhelp101):

yea. I was just easier then i thought, i guess that is good !

OpenStudy (abhisar):

do u live in paris ?

OpenStudy (superhelp101):

Thank you for your fantastic job at explaining! Nope the U.S.A but that pic that I took was at Las Vegas ? lolz

OpenStudy (superhelp101):

sorry no question mark!

OpenStudy (abhisar):

Vegas ^_^

OpenStudy (superhelp101):

haha. we were just exploring ≧◉◡◉≦ nothing else if you know what i mean !!

OpenStudy (abhisar):

heheheheh :D

OpenStudy (superhelp101):

xD

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