Question

Here's my other question....

Answer 1

Yes, yes Welcome.

Answer 2

\[\frac{ (6z^2-13z-15)(5z^2-8z-4)(2z^2-15z+28) }{ (z^2+2z-8)(2z^2-13z+21)(30z^2+37z+10) }\] here you go...............

Answer 3

you can try to factor every thing that you can.

Answer 4

What can you factor, and how ?

Answer 5

ok wait....

Answer 6

hi

Answer 7

hi dan

Answer 8

factor factor factor

Answer 9

`NUMERATOR:`
6z²-13z-15 = (6z+5)(z-3)
5z²-8z-4 = (5z+2)(z-2)
2z²-15z+28 = (2z-7) `(z-4)`
──────────────────
`DENOMINATOR:`
z²+2z-8 = `(z+4)`(z-2)
z²-13z+21 = (2z-7)(z-3)
30z²+37z+10 = (6z+5)(5z+2)

I grayed the factors that don't cancel.

Answer 10

that was fast....I was just starting....

Answer 11

just finished

Answer 12

Cool !

Answer 13

\[\frac{ z-4 }{ z+4 }\] right?

Answer 14

yes

Answer 15

Awesome....I just need to push a little harder then I'll get the complex fractions yes.....

Answer 16

:)

Answer 17

how about this?

Answer 18

\[\frac{ ax+ay-bx-by }{ am-bm-an+bn }\]

Answer 19

i think i got this one...

Answer 20

Numerator = (a-b)(x+y)
Denominator = (a-b)(m-n)

Answer 21

thats my answer actually....

Answer 22

and it turns out to be \[\frac{ x+y }{ m-n }\]

Answer 23

last one

Answer 24

\[\frac{ 27x^3 }{ 225x^5 }\]

Answer 25

how is that?

Answer 26

xD

Answer 27

okay what do u think it is

Answer 28

I dont know.......I had hard time on it....

Answer 29

3^3 x*x*x
---------------
(200+25) x*x*x*x*x


3^3 x*x*x
---------------
(99+99+27) x*x*x*x*x

Answer 30

how will the xs cancel