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Mathematics 14 Online
OpenStudy (anonymous):

What is the center of the circle given by the equation (x - 3)2 + (y - 9)2 = 16? A. (3, 9) B. (-9, -3) C. (9, 3) D. (-3, -9)

OpenStudy (anonymous):

@ganeshie8

OpenStudy (anonymous):

@mathstudent55

OpenStudy (anonymous):

@MaimiGirl

OpenStudy (anonymous):

think of it this way (x-h)^2 + (y-k)^2 = r^2 in which, (h,k) is the center

OpenStudy (anonymous):

so its (-3,-9) :)

OpenStudy (anonymous):

wrong look again

OpenStudy (anonymous):

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