Question

factor fully

Answer 1

\[3(x-1)^{2}+5(1-x)\]

Answer 2

use
\[(a-b)^2=a^2-2ab+b^2\]

Answer 3

find out (x-1)^2 using this

Answer 4

can u do it?

Answer 5

yeah its 3(x^2+2x+1) 5(1-x)

Answer 6

just a little wrong
\[(x-1)^2=x^2-2*x*1+1=x^2-2x+1\]
so \[ 3(x^2-2x+1)=3x^2-6x+3\]
okay so far?

Answer 7

yes i do, whats the next step?

Answer 8

so finally-
\[3(x-1)^2+5(1-x)=3x^2-6x+3+5-5x\]\[=3x^2-11x+8\]

Answer 9

got this?

Answer 10

oh i gotcha, thanks for clarifying, I just didnt know what sums would factor in 3x^2-11x+8

Answer 11

np :)