There are 5 beaches competing to be the family friendliest beach according to one travel magazine. If only the top 3 are ranked - first, second, and third - how many different ways can the list appear?

A. 15 ways
B. 30 ways
C. 60 ways
D. 10 ways

Question

There are 5 beaches competing to be the family friendliest beach according to one travel magazine.  If only the top 3 are ranked - first, second, and third - how many different ways can the list appear?

        


	A.	15 ways
	B.	30 ways
	C.	60 ways
	D.	10 ways

anonymous · Answer

Can someone help me with this problem?

dape · Answer

Any of the 5 beaches could be at first place. Keeping this in mind, we see that any 4 of the beaches left could be second place. So there are 5*4=20 combinations of first and second place. By the same argument, any of the 3 beaches left could be third place. In total, this gives us 60 different lists, since 60=5*4*3.

anonymous · Answer

@dape that's right :)