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OpenStudy (superhelp101):
What is the equation, in standard form, of a horizontal hyperbola with asymptotes at (see below) open parentheses x plus 6 close parentheses squared over 36 end fraction minus open parentheses y minus 6 close parentheses over 121 = 1 open parentheses x minus 6 close parentheses squared over 36 end fraction minus open parentheses y plus 6 close parentheses over 121 = 1 open parentheses x plus 6 close parentheses squared over 121 end fraction minus open parentheses y minus 6 close parentheses over 36 = 1 open parentheses x minus 6 close parentheses squared over 121 end fraction minus open parentheses y plus 6 close parentheses over 36 = 1
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