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Mathematics 18 Online
OpenStudy (tester97):

26. If f(x) = (x + 1)2, then f(t + 2) = A) t2 + 2t + 4 B) t2 + 4 C) t2 + 6t + 9 D) t2 + 9 E) t2 + 2t + 1

OpenStudy (anonymous):

Replace the x with the (t+2) as it's a function of x. expand.

OpenStudy (anonymous):

i think its C not sure

OpenStudy (anonymous):

its A. Dead sure

OpenStudy (anonymous):

Imeant C.

OpenStudy (tester97):

So ken u knot try to confuse me? kthx I am trying to learn here~ Is your answer legit?

OpenStudy (anonymous):

(t+@+1)^2 = ?

OpenStudy (tester97):

\[(t+2+1)^2\rightarrow (t+2+1)\times(t+2+1)\] then evaluate that and i get t^2+6t+9

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