PLEASE HELP MEEE!! Are these functions even or odd and how did u find that? 2/x^2, 4 square root of x, x^5-2x^3+x

Question

campbell_st · Answer

well just subsitute -x for x and see if you get the original function 

if f(-x) = f(x) then the function is even 

   f(-x) = -f(x) the function is odd

and lastly if neither is true, then the function is neither odd nor even

thats the theory... 

so for the 1st 

$$f(-x) = \frac{2}{(-x)^2}$$

can you simplify this..?

anonymous · Answer

Wouldn't the (-x)^2 just become an x^2 again? so the function is even?