What are the foci of the hyperbola given by the equation 16x2 - 25y2 - 64x - 50y - 361 = 0?

(-1 ± square root of 41 , 2)
(2 ± square root of 41, -1)
(-1, 2 ± square root of 41)
(2, -1 ± square root of 41)
last one then I won't bother u anymore, darling

Question

What are the foci of the hyperbola given by the equation 16x2 - 25y2 - 64x - 50y - 361 = 0?
 	
	(-1 ± square root of 41 , 2)
	(2 ± square root of 41, -1)
	(-1, 2 ± square root of 41)
	(2, -1 ± square root of 41)
last one then I won't bother u anymore, darling <33333333 I have a feeling it's the second option

superhelp101 · Answer

@study100 <333333333 <33333

anonymous · Answer

Yes, it's the second option! :) <3333

anonymous · Answer

You're so smart <3

superhelp101 · Answer

You're the smartest!!!!!! <33333 I love you!!!!

anonymous · Answer

Love love you... too :) huggles <3

superhelp101 · Answer

huggles to you too!!!!!!!!!!