Question

HELP!!!!!! Solve 64^x = 16^(x−1) A. x = −2 B. x = −1 C. x = -1/4 D. x = -1/3

Answer 1

64x = 16x - 1 (subtract 16x from both sides)
64x - 16x = -1 (combine like terms)
48x = -1 (divide both sides by 48)
x = -1/48

is your problem written correctly ?

Answer 2

i was actually just rewriting it as you commented!

Answer 3

sorry...I am so not good at thise types of problems

Answer 4

It's okay! thanks for trying :)