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HELP!!!!!! Solve 64^x = 16^(x−1) A. x = −2 B. x = −1 C. x = -1/4 D. x = -1/3
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64x = 16x - 1 (subtract 16x from both sides) 64x - 16x = -1 (combine like terms) 48x = -1 (divide both sides by 48) x = -1/48 is your problem written correctly ?
i was actually just rewriting it as you commented!
sorry...I am so not good at thise types of problems
It's okay! thanks for trying :)
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