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what are 3 consecutive intergers whoes sum is 114
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can you think of 3 consecutive numbers?
1 2 and 3
37 + 38 + 39. There's an algebraic way to solve this but it's too much work, so you're better off just guessing and checking
hmmm I see 1 is the first one.. how did you get the 2nd one? number 2? and how did you get the 3rd one, number 3?
n + (n+1) + (n+2) = 114 3n + 3 = 114 3n = 111 n = 37.
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Then plug 37 into n+1 and n+2 and voila
ridoleor, I would make x the middle number, that would be easier to solve.
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