A local store owner pays her employees time-and-a-half for overtime. That means for every hour an employee works more than 40 hours per week, the store will pay 1.5 times the regular hourly wage of $8.50.
Combine the two functions you just wrote to form a piecewise function, W(x), in which each function is defined for a specific domain.

Question

A local store owner pays her employees time-and-a-half for overtime. That means for every hour an employee works more than 40 hours per week, the store will pay 1.5 times the regular hourly wage of $8.50.
Combine the two functions you just wrote to form a piecewise function, W(x), in which each function is defined for a specific domain.

samsan9 · Answer

sorry there was another part to this problem that was solved earlier

loser66 · Answer

Your attempt?

samsan9 · Answer

i dont really know what a piecewise fnction is...

samsan9 · Answer

260+(h-40)(9.75) do you think this could be the answer?

loser66 · Answer

Now, just regular working ( I mean not over time)
the salary is S1 = 8.50*h    , h $\leq $40  where h is hour

loser66 · Answer

Over time function
S2= 340 + 12.75 *(h-40) when h >40
Let me explain why we have those numbers
340 =8.5*40 because for 40 hours, they are paid regular salary 
12.75 = 1.5*8.5, this number is overtime salary. This salary applied for overtime only. So that it is timed to the hours they work more than usual. right?
for example, you work 41 hours. the first 40 hours costs 40*8.5 = 340
                                                   the 1more hour cost 12.75 *1  =    12.75
                                                   total, you get  352.75 , right?
Now, apply our formula S2= 340 +12.75 * (41-40) =352.75  THE SAME

samsan9 · Answer

can you help me with the last part?

samsan9 · Answer

Determine how much an employee will be paid if he or she were to work 50 hours in a week.

loser66 · Answer

$$W(x)=\begin{cases}8.50*x ~~~~if~~~x\leq 40\340+12.75(x-40)~~~if~~x>40\end{cases}$$

samsan9 · Answer

is that the answer?