Question

Find the equation of the quadratic function with zeros 10 and 14 and vertex at (12, -8).

y = 2x2 + 48x + 280

y = -2x2 - 48x + 280

y = -2x2 + 48x - 280

y = 2x2 - 48x + 280

Answer 1

i factored it but i didn't got one of your choices for some reason

(x-10)(x-14)

I think after you factor it u substitute the vertex at (11 , -2)
y=a((x-10)(x-14))

but that's not the end though

Answer 2

but make sure u factor (x-10)(x-14) first

Answer 3

and then substitute

Answer 4

I'm not sure how to do that. I am unfortunately pretty bad at math :/

Answer 5

factor (x-10)(x-14), can you factor it out by using the foil method?

Answer 6

2x-14x-10x+140?

Answer 7

Well, FOIL stands for First, Outer, Inner, Last.
(x-10)(x-14) =(x · x+x · -10-14 · x-14 · -10)

Answer 8

2x-14x-10x+140 is wrong, u first multiply the first factors