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evaluate f(2) for the function f(x). f(x)=5x^2+3x-6 1.32 2.112 3.8 4.20
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Just sub x for 2
\[ f(2)=5(2)^2+3(2)-6 \]
5 times 2 is 10
soo \[ f(2)=10^2+3(2)-6 \]
10^2 = 100
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so \[ f(2)=100+3(2)-6 \]
then 3 times 2 is 6 and you subract 6 so... \[f(2)=100\]
:)
It's 5*(2)^2 NOT (5*2)^2
\[5x ^{2}+3x-6\] Substitute x=2 gives \[5(2)^{2}+3(2)-6\] Solve that for your answer
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