Question

I need help on a question. I'll post it below.

Answer 1

\[\frac{ 16a^2bc }{ 4ac^2 }\] Simplify

Answer 2

In expanded form its

\[\frac{4 \times 4 \times a \times b \times c}{4\times a \times c \times c}\]

just remove the common factors... what's left is the answer

Answer 3

\[\frac{4 \times 4 \times a \times a \times b \times c}{4\times a \times c \times c}\]

Answer 4

\[\frac{ 4ab }{ c }\]

Answer 5

oops... missed an a in the numerator... look at @aum

Answer 6

looks good to me

Answer 7

thank you @campbell_st and @aum

Answer 8

You are welcome.