How can I factor 2(x+3)^-4/3 + (x+3)^-1/3 @SolomonZelman

Question

jdoe0001 · Answer

$\large \bf {
2(x+3)^{-\frac{4}{3}}+(x+3)^{-\frac{1}{3}}
\ \quad \
 2(x+3)^{-\frac{1}{3}-\frac{3}{3}}+(x+3)^{-\frac{1}{3}} }$

solomonzelman · Answer

$\normalsize\color{blue}{   2(x+3)^{-4/3}+(x+3)^{-1/3}   }$


$\LARGE\color{blue}{   2\frac{1}{\sqrt[3]{(x+3)^4}}+\frac{1}{\sqrt[3]{(x+3)}}   }$


$\LARGE\color{blue}{   2(x+3)\frac{1}{\sqrt[3]{(x+3)}}+\frac{1}{\sqrt[3]{(x+3)}}   }$


$\LARGE\color{blue}{   2(x+3)\frac{1}{\sqrt[3]{(x+3)}}+1\frac{1}{\sqrt[3]{(x+3)}}   }$


$\LARGE\color{blue}{  [ 2(x+3)+1]\frac{1}{\sqrt[3]{(x+3)}}  }$


$\LARGE\color{blue}{  [ 2x+6+1]\frac{1}{\sqrt[3]{(x+3)}}  }$


$\LARGE\color{blue}{ (2x+7)\frac{1}{\sqrt[3]{(x+3)}}  }$

anonymous · Answer

Thanks @SolomonZelman