Question

I really really need help on this worksheet.
http://static.k12.com/eli/bb/1212/4_69102/1_124271_18_69120/53c4a7c98dfaf2fab28d00306dcf5e27b4b52d7f/media/6957c2156cbdcd4bde93f53ab410f3e14ba0159d/AAHS_M9S5L9_2_teacher_graded_assignment_PROJECTGUIDE.pdf
K12 Inc.

Answer 1

help badly and fast

Answer 2

which question(s)?

Answer 3

all...

Answer 4

for #1, use n = 1, n=2, n=3, n=4, n=5. \[t _{1}=-3(1)+55\]That equals 52. Next one is\[t _{2}=-3(2)+55=49\]

Answer 5

\[t _{3}=-3(3)+55=46\]

Answer 6

\[t _{4}=-3(4)+55=43\]\[t _{5}=-3(5)+55=40\]So the first 5 terms are 52, 49, 46, 43, 40

Answer 7

oh okay. that kinda makes sense

Answer 8

For #2, do the same but for a geometric sequence instead of an arithmetic one. Done the same way but with multiplication instead of addition.

Answer 9

Q3.
common difference is 6
rule: 6n-21

Answer 10

so tenth term, simply 6(10)-21=?

Answer 11

\[t _{1}=5\times 2^{1-1}=5\]

Answer 12

@Auxuris 39?

Answer 13

\[t _{2}=5\times 2^{2-1}=10\]

Answer 14

\[t _{3}=5\times 2^{3-1}=20\]

Answer 15

\[t _{4}=5\times 2^{4-1}=40\]\[t _{5}=5\times2^{5-1}=80\]So the first five terms are 5, 10, 20, 40 80

Answer 16

oh okay still trying to process. Help on 4?

Answer 17

@Auxuris how do I do #3 again?

Answer 18

yes, the answer is 39, hang on, i'm trying to figure out Q4

Answer 19

alright thanks so much