Question

Simplify 10 over quantity of 8 minus 5 i.

Answer 1

Multiply by the conjugate
\[ \frac{10}{8-5i}=\frac{10}{8-5i}\frac{8+5i}{8+5i}\]

Answer 2

Alright after that then what?

Answer 3

multiply out the numerator and denominator

Answer 4

How do I do that?

Answer 5

just like with regular numbers...
\[ \frac{10(8+5i)}{(8-5i)(8+5i)}\]

Answer 6

Would you mind breaking it down a little more? I've had 4 hours of sleep in the last two days haha I'm a little slow today

Answer 7

\[\frac{10(8+5i)}{(8-5i)(8+5i)}=\frac{10(8)+10(5i)}{8(8)+8(5i)-5i(8)-5i(5i)}\]

Answer 8

so the answer is
quantity of 80 plus 50 i over 89 ??

Answer 9

yup

Answer 10

awesome thanks

Answer 11

yw :)