Question

Find the missing coefficient.
(4d-4)(3d-2)=12d^2+blank d+8

Answer 1

LHS = (4d-4)(3d-2)
= (4d)(3d) + (4d)(-2) + (-4)(3d) + (-4)(-2)
= 12d^2 – 8d – 12d +8
= 12d^2 – 20d + 8 ------ (1)
But RHS = 12d^2 + _d + 8 ---------(2)
Therefore from (1) and (2),
Missing Coefficient is -20.