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help me find the frequency of d = 2 sin ((pi/3)t)!!
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What's the period of that trig equation?
ummm... i struggle with periods as well .-.
y = A*sin(Bx - C) + D is the general equation with period T = 2pi/B
In this case, B = pi/3
T = ??
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2pi/(pi/3)?
so..six?
T = 6, yep
The frequency f is found by this formula f = 1/T
so the answer is 1/6?
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correct
thanks a ton! a lot of stuff just cleared up!
I'm glad it has
sooo, for d = 9 cos ((pi/2)t), would the period be 4? @jim_thompson5910
good
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thanks :)
np
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