Question

simplify:

sinθcosθ / tanθ

Answer 1

cos^2 (Theta)

Answer 2

Well

\[\large \frac{sin(x)cos(x)}{tan(x)}\]

we know tan = sin/cos so

\[\large \frac{sin(x)cos(x)}{\frac{sin(x)}{cos(x)}}\]

Flip and multiply

\[\large \cancel{sin(x)}cos(x) \times \frac{cos(x)}{\cancel{sin(x)}}\]

\[\large cos(x) \times cos(x) = cos^2(x)\]

Answer 3

thank you both!!!!!

Answer 4

Anytime :)