Question

Four polynomial functions are shown below:

f(x) = x3 + 3x2 - 4x - 12
g(x) = x3 - 3x - 2
p(x) = x2 + 3x + 2
t(x) = x2 + x - 2

Which of the following functions has -1 and -2 as its zeros?

f(x)

g(x)

p(x)

t(x)

Answer 1

factor each answer choice to find out.

Answer 2

Don't know why you are posting a MATH question i n history, though :)

Answer 3

\(\normalsize\color{black}{ f(x)=x^3 + 3x^2 - 4x - 12 }\)

\(\normalsize\color{black}{ x^3 + 3x^2 - 4x - 12 =0}\)

\(\normalsize\color{black}{ x^2(x+3) - 4(x+3) =0}\)

\(\normalsize\color{black}{ (x^2-4)(x+3)=0}\)

\(\normalsize\color{black}{ (x-2)(x+2)(x+3)=0}\)

ZEROS, \(\normalsize\color{black}{ 2,~~-2,~~~~~3}\) .

Answer 4

\(\normalsize\color{black}{ g(x)=x^3 - 3x - 2}\) will have non-integer zeros.

Answer 5

\(\normalsize\color{black}{ p(x)=x^2 +3x+2}\)

\(\normalsize\color{black}{ p(x)=(x+2)(x+1)}\)

\(\normalsize\color{black}{ ~~-2,~~~~-1}\)