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In how many ways can a committee of 5 people be chosen from a total of 30 possible people? 105, 729 112,098 123,567 142,506
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30 C 5 = 30*29*28*27*26 --------------- 5*4*3*2*1
30!/(25!)(5!)=(30*29*28*27*26)/(5*4*3*2*1)
142,506
Ways=30C5=30*29*28*27*26/5*4*3*2*1
combinations = 30! / (5!) * (25!) combinations = 30*29*28*27*26/ 5*4*3*2*1 combinations = 30*29*28*27*26 / 120 =17100720/120 =142,506
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