Question

I need help with a parabola. Please help me out.

Answer 1

I need to come up with an equation, but im stuck

Answer 2

Did you learn the conics formulas?

Answer 3

No, parabolas
y= a(x-h)^2 + k

Answer 4

ohh yes I know that one

Answer 5

like on here, first section
https://www20.csueastbay.edu/library/scaa/files/pdf/Conics.pdf

Answer 6

the h would be 0 and the k 57 right?

Answer 7

yes, so you plug it in
y= a(x-0)^2 + 57

Now all you need to do is find a.

Pick a point that that graph that is not the vertex? then let's cont

Answer 8

33,0

Answer 9

ok plug 0 in for y
plug 33 in for x

0= a(33-0)^2 + 57
0= a (33)^2 + 57
0=1089a +57
a= -57/1089
a= -19/363 = -0.0523

Answer 10

so my final equation would be y=-0.0523(x-0)^2+57

Answer 11

now get it all together and we have the equation
y= -0.0623x^2 + 57

Answer 12

yeah and x-0 is just x

Answer 13

ohh okay that was simple

Answer 14

thanks a lot

Answer 15

you're welcomed buddy :)

Answer 16

ok tell me where it's confusing.

Answer 17

lemme know so I can help you :) it's ok

Answer 18

@study100 I figured it out i just mixed up the numbers thanks though