Question

Solve for x.

-ax + 4b > 9

answers:

x > the quantity negative 3 times b minus 5 all over negative a

x < the quantity 5 minus 3 times b all over negative a

x < the quantity negative 3 times b plus 5 all over negative a

x > the quantity negative 3 times b plus 5 all over negative a

Answer 1

First you subtract 4b from both sides. Then you divide both sides by -a to fully isolate x.


Keep in mind that dividing both sides by a negative number will flip the inequality sign.


\[\Large -ax + 4b > 9\]

\[\Large -ax > 9 - 4b\]

\[\Large x < \frac{9 - 4b}{-a}\]

Answer 2

Thanks so much @jim_thompson5910

Answer 3

you're welcome