Question

arcsin root3/2

Answer 1

\[\arcsin~ (\frac{\sqrt{3}}{2}) = \sin^{-1} (\frac{\sqrt{3}}{2})\]

This is essentially asking us:

\(\sin\) of what angle is \[\frac{\sqrt{3}}{2}\]
? :D

Answer 2

and for my answer i got pi/3? :)

Answer 3

Correct!
\[\sin (\frac{\pi}{3}) = \sin (60') = \frac{\sqrt{3}}{2}\]

Answer 4

arcsin 0 and arccos 1 are both 2pi right? thanks so much btw!