Question

factorization of polynomials: 16u^8 - 8u^4 + 1

Answer 1

since the degree is of the 1st term is just the double of the 1nd term... we can reduce it to quadratic form...

Answer 2

then apply quadratic formula...

Answer 3

16u^8 - 8u^4 + 1
=(4u^4)^2 -2*(4u^4)(1) +1
=(4u^4 - 1)^2

Answer 4

=(4u^4 - 1)^2
= ( (2u^2)^2 - 1) ^2
= ( (2u^2)- 1) * (2u^2) + 1) )^2

Answer 5

what happens to the plus one? @matricked