Question

sin^2 x = 1/2 on the interval of [0,2)

Answer 1

so
2sin^2 x = 1
or
1-2sin^2 x =0
or cos2x =0
so
2x= (2n+1)*pi/2 where n is integer
or x= (2n+1)*pi/4
now put the values of n and chose those x which falls under the given interval

Answer 2

what happens to the 1/2?

Answer 3

cross multiplied

Answer 4

i dont understand what to do. can you please explain it to me?