Question

Find the standard form of the equation of the parabola with a focus at (0, 6) and a directrix at y = -6.

Answer 1

@bradely

Answer 2

@ganeshie8

Answer 3

vertex = midpoint of directrix and focus = (0, 0)

Answer 4

So the equation will be of form :

\[\large y = \dfrac{1}{4c}x^2\]

Answer 5

c=6 here, cuz directrix is y = -6 = -c

that makes the required equation :

\[\large y = \dfrac{1}{4*6}x^2\]

Answer 6

\[\large y = \dfrac{1}{24}x^2\]