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Trigonometry
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sin(B-A) is equal to ?????????? when B= 270 degrees and A is an acute angle.
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okay first how many degrees are in an acute angle
90 degrees
okay now plug them in
sin90cos270+cos90sin270
Am I right?
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yeah
thats the correct answer?
do you know how to double check?
No
is this homework or an online thing ?
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homework
okay, does it say to simplify on the expressions ?
no
but what if i need to ?
sin (270 - A) = -cos A Since Sin (270 - A) lies in the 3rd Quadrant. In the 3rd Quadrant the value of sin is Negative.
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