Does anyone know how to solve for x?
https://banff.owschools.com/media/g_geo_2013/7/group186.gif

Question

Does anyone know how to solve for x?
https://banff.owschools.com/media/g_geo_2013/7/group186.gif

nikato · Answer

Call the unlabeled arc length in the semicircle, y

There's a theorem that states

10= 1/2 (30-y)
Solve for y

nikato · Answer

Once you solve for y, you know a semicircle=180

So
180=30 + y + x

anonymous · Answer

x=120?

nikato · Answer

No.
What did you get for y?

anonymous · Answer

10

anonymous · Answer

is it 100 then? :o

nikato · Answer

10 is correct.

180= 30+10+x
180=40+x
-40.     -40
------------
x=?

anonymous · Answer

i see. okay thank you!Could you help me in solving one more question?

nikato · Answer

Ok. And sure

anonymous · Answer

i have a ton of questions just like this https://banff.owschools.com/media/g_geo_2013/7/group146.gif m∠1 = _° I get confused withh arcs..lol

anonymous · Answer

i think i just get all these theorems and things mixed up!

nikato · Answer

Same theorem

That angle = 1/2 ( major arc - minor arc)

nikato · Answer

So <1= 1/2 (140-40)

anonymous · Answer

okay i get it now!!!

nikato · Answer

Yea. Shouldn't be that hard once you know what formula to use