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OpenStudy (anonymous):
Evaluate the definite integral: can someone check my work to see if I'm doing this correctly ∫(6x2+2x−3)dx ∫6x2dx+∫172xdx−∫173dx 6∫x2dx=2x3+2∫17xdx−∫173dx =2x3+x2−3x+c =x(2x2+x−3)+c =7(2(7)2+7−3)=714
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