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transformation trigo integral
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did you try t = tan x ?
yes. i got dt= sec^2 x dx
also write \(sec^4 = sec^2 \times sec^2 \) write one\( sec^2 = 1+tan^2 \)
\(\sqrt t s^4 = \sqrt t s^2 \times s^2 dx = \sqrt t (1+t^2) \times s^2 dx\) and you already got s^2 dx =dt
t = tan s= sec
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Okay, im following =)
whats your new integral in terms of t ?
wait. ill solve this. =)
could you solve ? any doubts ?
yes
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i got |dw:1407069695180:dw|
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