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please help me sin A cos B = p sin (A-B) = q cot A tan B = .... ?
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sinAcosB-cosAsinB=q sinAcosB=p cosAsinB=p-q cotA=cosA/sinA tanB=sinB/cosB cotA tanB=cosA/sinA *sinB/cosB =cosAsinB/sinAcosB =(p-q)/q
@nirmalnema so, option E is correct? a. 1 - (q/p) b. 1 + (q/p) c. 1 - (p/q) d. 1 + (p/q) e. (p/q) - 1
oh wait. i dont think so
It looks like a typo in the last line of nirm's post he meant (p-q)/p
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