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OpenStudy (anonymous):
Nicole missed the lesson on normal distribution and needs to do her homework. Explain to Nicole how to use the mean and standard deviation of a normal distribution to determine the top 5% of the population.
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OpenStudy (sidsiddhartha):
ok do u have the z-chart with u?
OpenStudy (anonymous):
whoops, z chart?
OpenStudy (sidsiddhartha):
here \[\phi[\frac{ x-\mu }{ \sigma }]=1-0.05=0.95\] so \[\frac{ x-\mu }{ \sigma }=\phi(0.95)\] so u need to substitute the z-score of 0.95 here
OpenStudy (anonymous):
oh okay so that's all i have to do?
OpenStudy (sidsiddhartha):
yeah that'll be all after that u just have to put the values of \[\mu ,\sigma\]
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OpenStudy (anonymous):
so what formula is that called?
OpenStudy (sidsiddhartha):
uhh u can call it normal distibution formula where\[\mu=mean\]and \[\sigma=standard. deviation\]
OpenStudy (anonymous):
oh thanks so much
OpenStudy (sidsiddhartha):
np :)
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