Ask your own question, for FREE!
Mathematics 25 Online
OpenStudy (anonymous):

Medal for help :) For the data in the table , does y vary directly with x? if it does write an equation for the direct variation.

OpenStudy (anonymous):

OpenStudy (jdoe0001):

so.... does it?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

@HELP!!!!

OpenStudy (jdoe0001):

well.... let's take a look at the 1st point then x = 8 y = 11 so \(\bf \begin{array}{cccllll} \textit{something }&\textit{varies directly to }&\textit{something else}\\ \quad \\ \textit{something }&={\color{red}{ \textit{some value }}}&\textit{something else}\\ \quad \\ y&={\color{red}{ n}}&x&\implies y={\color{red}{ n}}x \end{array}\\ \quad \\ x= 8\qquad y=11\implies 11={\color{red}{ n}}(8)\) solve for "n", or "constant of variation" and then plug it back in the equation

OpenStudy (anonymous):

B

OpenStudy (jdoe0001):

n = B? well.... I think is a constant

OpenStudy (anonymous):

that's my answer

OpenStudy (anonymous):

y=06875x

OpenStudy (anonymous):

@am!rah

OpenStudy (anonymous):

@dan815

OpenStudy (anonymous):

Does anyone know what it is ?

OpenStudy (juanpablojr):

I don't know this sorry :(

OpenStudy (anonymous):

Ty anyway Juan

OpenStudy (anonymous):

@Destinymasha

OpenStudy (mathmale):

@juniorEinstein1: to live up to your user name, you're going to need to invest more time and effort into problem solving. Ignoring jdoe's question and then asking one person after another for help will not help you much in the long run. If you truly want to learn how to solve this kind of problem, go back to jdoe's input and see what you can come up with as a value for 'n'.

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!