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OpenStudy (anonymous):
Expand (2x - y)5.
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OpenStudy (amoodarya):
\[(a+b)^5=\left(\begin{matrix}5 \\ 0\end{matrix}\right) a^5 b^0 +\left(\begin{matrix}5 \\ 1 \end{matrix}\right)a^4b^1 +\left(\begin{matrix}5 \\ 2\end{matrix}\right) a^3b^2 +...+\left(\begin{matrix}5 \\ 5\end{matrix}\right)a^0b^5\]
OpenStudy (amoodarya):
now plug into it
a=2x
b=-y
OpenStudy (anonymous):
I did but I did not find the answer
OpenStudy (anonymous):
did you mean 5 times that amount or the amount to the 5th power?
OpenStudy (anonymous):
yes
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OpenStudy (amoodarya):
\[(a+b)^5=a^5 +5a^4b^1+10a^3b^2+10a^2b^3+5a^1b^4+b^5\]
OpenStudy (anonymous):
32x5 + 400x4y + 2000x3y2 + 5000xy2 + 6250xy4 + 3125y5
32x5 + 400x4y - 2000x3y2 + 5000xy2 - 6250xy4 + 3125y5
32x5 - 400x4y + 2000x3y2 - 5000xy2 + 6250xy4 - 3125y5
32x5 - 400x4y - 2000x3y2 + 5000xy2 + 6250xy4 + 3125y5
OpenStudy (anonymous):
that's my answer choices
OpenStudy (amoodarya):
\[(2x)^5 +5(2x)^4 (-y)^1 +10(2x)^3(-y)^2+10(2x)^2(-y)^3 +5(2x)^1(-y)^4 +(-y)^5 =\\32x^5 -5(16)x^4y +10(8)x^3y^2-10(4)x^2y^3 +5(2)xy^4-y^5\]
OpenStudy (amoodarya):
your choices are not true
32x5 -80x4y +80x3y2 -40x2y3+10xy4-y5
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OpenStudy (anonymous):
thank you
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