Question

I hope someone can help me with this, because I have no idea how to do it!
and if you could please show me how to do it would be amazing! Thanks!

A missile is launched from the ground. Its height, h(x), can be represented by a quadratic function in terms of time, x, in seconds.
After 1 second, the missile is 110 feet in the air; after 2 seconds, it is 200 feet in the air.
Find the height, in feet, of the missile after 4 seconds in the air.

Answer 1

let h(x)=a x^2 + bx +c

Answer 2

we need to find a,b,c from the given conditions

Answer 3

okay

Answer 4

when x=0 h =0 means c=0
when x=1 h=110 means 110 = a+b
when x=2 h=200 means 200 = 4a+2b
so we need to solve
a+b= 110
and 4a+2b =200

Answer 5

i hope u can do further

Answer 6

im not sure how to do these, but I'll try it

Answer 7

i got 320

Answer 8

Thank you matricked!

Answer 9

a+b =110
2a+b= 100
subtracting the aboe two eq we have -a= 10 or a=-10
hence
b= 120

Answer 10

we need h when x=4
so
h= -10*16 + 120*4=480-160 =320