Question

Find the nth partial sum

Answer 1

\[\sum_{n=2}^{\infty} \ln(1-\frac{ 1 }{ n ^{2} } ) = \ln(1-\frac{ 1 }{ 4 } ) + \ln(1-\frac{ 1 }{ 9 } ) + \ln(1-\frac{ 1 }{ 16} ) + \ln(1-\frac{ 1 }{ 25 } )\]